What is (2+1000x10000)x0 ?
- Chappie
- Posts : 10
Reputation : 4
Join date : 2016-10-30
Age : 26
Location : Nova Scotia
Re: Poll of the day! (2)
Wed Nov 02, 2016 1:54 am
Well, since this is gone, I will take the liberty of answering it for those who got it wrong, or hate math.
- You would start with taking bedmas into account.
- Brackets take priority, so then it follows that we start with (2+1000x10000)
- Once again, bedmas takes effect and we are now working with 1000x10000, which comes out to 10,000,000.
Now we are left with (2+10,000,000)x0
- Bedmas tells us to start with (2+10,000,000)
- That gives us a grand total of 10,000,002.
- All that we are left with is 10,000,002 x 0, in which is 0.
Therefore, (2+1000x10000)x0 = 0
Edited by: a Math god: the 2 is the edited mistake
- You would start with taking bedmas into account.
- Brackets take priority, so then it follows that we start with (2+1000x10000)
- Once again, bedmas takes effect and we are now working with 1000x10000, which comes out to 10,000,000.
Now we are left with (2+10,000,000)x0
- Bedmas tells us to start with (2+10,000,000)
- That gives us a grand total of 10,000,002.
- All that we are left with is 10,000,002 x 0, in which is 0.
Therefore, (2+1000x10000)x0 = 0
Edited by: a Math god: the 2 is the edited mistake
- Chappie
- Posts : 10
Reputation : 4
Join date : 2016-10-30
Age : 26
Location : Nova Scotia
Re: Poll of the day! (2)
Wed Nov 02, 2016 1:55 am
I mean I could have condensed the statement into this function, (f(x)) x 0 = 0, but that wouldn't teach anyone anything at all now would it?
- Sven Shieldmaker
Posts : 116
Reputation : 3
Join date : 2016-10-06
Location : Virginia
Re: Poll of the day! (2)
Wed Nov 02, 2016 2:25 am
Theoretically, if using whole numbers, 0 might be representing anything from -.49999999 to .49999999.
Permissions in this forum:
You cannot reply to topics in this forum
|
|